In our latest MCQ Quiz, we’re excited to offer a valuable resource for aspiring chemistry scholars preparing for the CSIR NET, GATE, or JAM exams. Dive into our meticulously crafted Inorganic Chemistry Quiz, featuring a comprehensive set of multiple-choice questions (MCQs) that challenge your knowledge and understanding of the subject. What sets us apart? We provide not just the questions but also, at the end of the test, detailed solutions to help you grasp the concepts better. This is your opportunity to sharpen your inorganic chemistry skills and boost your exam readiness. Don’t miss out on this free and indispensable study aid to propel your success in these competitive exams.
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This test paper has a total of 55 questions carrying 110 marks. The entire question paper is divided in two sections, A and B. All sections are compulsory. Question in each section are different type.
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- Question 1 of 41
1. Question
2 pointsThe common feature (s) of Rb+, Kr and Br– is /are that they:
a) Have same number of valence electrons.
b) Have same magnitude of effective nuclear charge.
c) Have same magnitude of first Ionization potential.
d) Are iso-electronic speciesCorrectIsoelectronic species/ions/atoms are the species which have same number of electrons but different magnitude of nuclear charges & belongs to different atoms or ions.The isoelctronic ions with greater nuclear charge will have small size as compared to the ion with smaller nuclear charge.
Br– ion (35 + 1 = 36 electrons)
IncorrectIsoelectronic species/ions/atoms are the species which have same number of electrons but different magnitude of nuclear charges & belongs to different atoms or ions.The isoelctronic ions with greater nuclear charge will have small size as compared to the ion with smaller nuclear charge.
Br– ion (35 + 1 = 36 electrons)
- Question 2 of 41
2. Question
2 pointsThe species responsible for the superacidity of HSO3F–SbF5 system is
- HSO3F
- SbF5
- HF
- H2SO3F+
CorrectWhen SbF5 is added HSO3F reacts With itself to produce a molecule of H2SO3F+, containing a fluorine atom with a formal charge of +1 _ The F-H bond in this case is highly unstable, making this species a very strong acid.
2HSO3F + SbF5 ———-> H2S03F+ + SbFES03F-
Incorrect - Question 3 of 41
3. Question
2 pointsAmong the following the iso-electronic pair is
- NO and CO
- O2–(superoxide) and NO–
- NO+ and CO
- O2–(superoxide) and NO+
CorrectNO+ and CO
Are Elements or ions that have the same,or equal number of electrons.This module explorers that although ISOELECTRIC SPECIES have the same number of electrons,they are different in there physical and chemical properties.
IncorrectNO+ and CO
Are Elements or ions that have the same,or equal number of electrons.This module explorers that although ISOELECTRIC SPECIES have the same number of electrons,they are different in there physical and chemical properties.
- Question 4 of 41
4. Question
2 points1. The most polar compound amongs the following is
- SF4
- BF3
- XeF4
- SO3
CorrectBF3 is trigonal planar in shape due to the sp2 hybridized boron. The three fluorine atoms are at 120° to each other, so the vectors of their dipole moments add up to zero.
In SF4, the sulfur atom is sp3d hybridized. Four orbitals are used to bond with the fluorine atoms, while the fifth holds a lone pair. These fluorine atoms form a see-saw shaped molecule
IncorrectBF3 is trigonal planar in shape due to the sp2 hybridized boron. The three fluorine atoms are at 120° to each other, so the vectors of their dipole moments add up to zero.
In SF4, the sulfur atom is sp3d hybridized. Four orbitals are used to bond with the fluorine atoms, while the fifth holds a lone pair. These fluorine atoms form a see-saw shaped molecule
- Question 5 of 41
5. Question
2 pointsThe lattice energy of LiF calculated from Born Lande-equation is –1000 kJmol–1 . Assume that for both LiF and MgO the modelung constants, interionic distance and Born exponents have the same value.
The lattice energy of MgO in kJmol–1 is
CorrectBorax contains two tetrahedral units and two triangular units. Borax is used as a primary standard for titrating acids.
IncorrectBorax contains two tetrahedral units and two triangular units. Borax is used as a primary standard for titrating acids.
- Question 6 of 41
6. Question
2 pointsIn the structure of B4O5 (OH)42-CorrectIncorrect - Question 7 of 41
7. Question
2 pointsB2 H6 and B4 H10 respectively, are example of
CorrectFor closo boranes – BnHn^2-
Nido boranes – BnHn^4-
Arachno boranes – BnHn^6-IncorrectFor closo boranes – BnHn^2-
Nido boranes – BnHn^4-
Arachno boranes – BnHn^6- - Question 8 of 41
8. Question
2 pointsHydrolysis of (CH3)2SiCl2 and CH3SiCl3 leads to:
CorrectR2SiCl2 on hydrolysis gives Linear chain or ring polymerization while RSiCl3 gives cross linked silicone.
IncorrectR2SiCl2 on hydrolysis gives Linear chain or ring polymerization while RSiCl3 gives cross linked silicone.
- Question 9 of 41
9. Question
2 pointsThe compound having a S–S single bond is:
- H2S2O3
- H2S2O4
- H2S2O7
- H2S2O8
CorrectOption C and D have S-O-S linkage in it….so they are not the answer…and option A have S=S linkage in it…but the question asked is for S-S bond ..
which is present in Option B
IncorrectOption C and D have S-O-S linkage in it….so they are not the answer…and option A have S=S linkage in it…but the question asked is for S-S bond ..
which is present in Option B
- Question 10 of 41
10. Question
2 pointsThe atomicity and total number of bond in element white phosphorous molecules are, respectively
CorrectEXTRA INFO
Atoms in P4 molecule of white phosphorus are arranged regularly at the corners of a tetrahedron such that each atom is single-bonded to other three.The P−P−P bond angle is 60
.IncorrectEXTRA INFO
Atoms in P4 molecule of white phosphorus are arranged regularly at the corners of a tetrahedron such that each atom is single-bonded to other three.The P−P−P bond angle is 60
. - Question 11 of 41
11. Question
2 pointsA chemical compound [X] is used for water softening to remove temporary hardness [X] reacts with Na2CO3 to form caustic soda. When CO2 is bubbled through ‘X’ it becomes cloudy. The chemical formula of ‘X’ is
Correct<div id="react-mathjax-preview"> <div id="react-mathjax-preview-result"><span id="MathJax-Element-9-Frame" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="true"><mi>C</mi><mi>a</mi><msub><mrow><mo>(</mo><mi>O</mi><mi>H</mi><mo>)</mo></mrow><mrow><mn>2</mn></mrow></msub></mstyle></math>"><span id="MathJax-Span-84"><span id="MathJax-Span-85"><span id="MathJax-Span-86"><span id="MathJax-Span-87"><span id="MathJax-Span-88">C</span><span id="MathJax-Span-89">a</span><span id="MathJax-Span-90"><span id="MathJax-Span-91"><span id="MathJax-Span-92">(</span><span id="MathJax-Span-93">O</span><span id="MathJax-Span-94">H</span><span id="MathJax-Span-95">)</span></span><span id="MathJax-Span-96"><span id="MathJax-Span-97">2</span></span></span></span></span></span></span><span role="presentation">Ca(OH)2</span></span> is used for the softening of temporary hard water</div> </div> <div> <div id="react-mathjax-preview"> <div id="react-mathjax-preview-result"><span id="MathJax-Element-10-Frame" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="true"><mi>C</mi><mi>a</mi><msub><mrow><mo>(</mo><mi>O</mi><mi>H</mi><mo>)</mo></mrow><mrow><mn>2</mn></mrow></msub><mrow><mo>(</mo><mi>a</mi><mi>q</mi><mo>)</mo></mrow><mo>+</mo><mi>C</mi><msub><mi>O</mi><mrow><mn>2</mn></mrow></msub><mrow><mo>(</mo><mi>g</mi><mo>)</mo></mrow><mo>→</mo><munder><mrow><mi>C</mi><mi>a</mi><mi>C</mi><msub><mi>O</mi><mrow><mn>3</mn></mrow></msub><mrow><mo>(</mo><mi>s</mi><mo>)</mo></mrow><mo>+</mo><msub><mi>H</mi><mrow><mn>2</mn></mrow></msub><mi>O</mi><mrow><mo>(</mo><mi>l</mi><mo>)</mo></mrow></mrow><mrow><mrow><mtext>cloudiness</mtext></mrow></mrow></munder></mstyle></math>"><span id="MathJax-Span-98"><span id="MathJax-Span-99"><span id="MathJax-Span-100"><span id="MathJax-Span-101"><span id="MathJax-Span-102">C</span><span id="MathJax-Span-103">a</span><span id="MathJax-Span-104"><span id="MathJax-Span-105"><span id="MathJax-Span-106">(</span><span id="MathJax-Span-107">O</span><span id="MathJax-Span-108">H</span><span id="MathJax-Span-109">)</span></span><span id="MathJax-Span-110"><span id="MathJax-Span-111">2</span></span></span><span id="MathJax-Span-112"><span id="MathJax-Span-113">(</span><span id="MathJax-Span-114">a</span><span id="MathJax-Span-115">q</span><span id="MathJax-Span-116">)</span></span><span id="MathJax-Span-117">+</span><span id="MathJax-Span-118">C</span><span id="MathJax-Span-119"><span id="MathJax-Span-120">O</span><span id="MathJax-Span-121"><span id="MathJax-Span-122">2</span></span></span><span id="MathJax-Span-123"><span id="MathJax-Span-124">(</span><span id="MathJax-Span-125">g</span><span id="MathJax-Span-126">)</span></span><span id="MathJax-Span-127">→</span><span id="MathJax-Span-128"><span id="MathJax-Span-129"><span id="MathJax-Span-130">C</span><span id="MathJax-Span-131">a</span><span id="MathJax-Span-132">C</span><span id="MathJax-Span-133"><span id="MathJax-Span-134">O</span><span id="MathJax-Span-135"><span id="MathJax-Span-136">3</span></span></span><span id="MathJax-Span-137"><span id="MathJax-Span-138">(</span><span id="MathJax-Span-139">s</span><span id="MathJax-Span-140">)</span></span><span id="MathJax-Span-141">+</span><span id="MathJax-Span-142"><span id="MathJax-Span-143">H</span><span id="MathJax-Span-144"><span id="MathJax-Span-145">2</span></span></span><span id="MathJax-Span-146">O</span><span id="MathJax-Span-147"><span id="MathJax-Span-148">(</span><span id="MathJax-Span-149">l</span><span id="MathJax-Span-150">)</span></span></span><span id="MathJax-Span-151"><span id="MathJax-Span-152"><span id="MathJax-Span-153">cloudiness</span></span></span></span></span></span></span></span></span></div> </div> </div>
Incorrect<div id="react-mathjax-preview"> <div id="react-mathjax-preview-result"><span id="MathJax-Element-9-Frame" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="true"><mi>C</mi><mi>a</mi><msub><mrow><mo>(</mo><mi>O</mi><mi>H</mi><mo>)</mo></mrow><mrow><mn>2</mn></mrow></msub></mstyle></math>"><span id="MathJax-Span-84"><span id="MathJax-Span-85"><span id="MathJax-Span-86"><span id="MathJax-Span-87"><span id="MathJax-Span-88">C</span><span id="MathJax-Span-89">a</span><span id="MathJax-Span-90"><span id="MathJax-Span-91"><span id="MathJax-Span-92">(</span><span id="MathJax-Span-93">O</span><span id="MathJax-Span-94">H</span><span id="MathJax-Span-95">)</span></span><span id="MathJax-Span-96"><span id="MathJax-Span-97">2</span></span></span></span></span></span></span><span role="presentation">Ca(OH)2</span></span> is used for the softening of temporary hard water</div> </div> <div> <div id="react-mathjax-preview"> <div id="react-mathjax-preview-result"><span id="MathJax-Element-10-Frame" role="presentation" data-mathml="<math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle displaystyle="true"><mi>C</mi><mi>a</mi><msub><mrow><mo>(</mo><mi>O</mi><mi>H</mi><mo>)</mo></mrow><mrow><mn>2</mn></mrow></msub><mrow><mo>(</mo><mi>a</mi><mi>q</mi><mo>)</mo></mrow><mo>+</mo><mi>C</mi><msub><mi>O</mi><mrow><mn>2</mn></mrow></msub><mrow><mo>(</mo><mi>g</mi><mo>)</mo></mrow><mo>→</mo><munder><mrow><mi>C</mi><mi>a</mi><mi>C</mi><msub><mi>O</mi><mrow><mn>3</mn></mrow></msub><mrow><mo>(</mo><mi>s</mi><mo>)</mo></mrow><mo>+</mo><msub><mi>H</mi><mrow><mn>2</mn></mrow></msub><mi>O</mi><mrow><mo>(</mo><mi>l</mi><mo>)</mo></mrow></mrow><mrow><mrow><mtext>cloudiness</mtext></mrow></mrow></munder></mstyle></math>"><span id="MathJax-Span-98"><span id="MathJax-Span-99"><span id="MathJax-Span-100"><span id="MathJax-Span-101"><span id="MathJax-Span-102">C</span><span id="MathJax-Span-103">a</span><span id="MathJax-Span-104"><span id="MathJax-Span-105"><span id="MathJax-Span-106">(</span><span id="MathJax-Span-107">O</span><span id="MathJax-Span-108">H</span><span id="MathJax-Span-109">)</span></span><span id="MathJax-Span-110"><span id="MathJax-Span-111">2</span></span></span><span id="MathJax-Span-112"><span id="MathJax-Span-113">(</span><span id="MathJax-Span-114">a</span><span id="MathJax-Span-115">q</span><span id="MathJax-Span-116">)</span></span><span id="MathJax-Span-117">+</span><span id="MathJax-Span-118">C</span><span id="MathJax-Span-119"><span id="MathJax-Span-120">O</span><span id="MathJax-Span-121"><span id="MathJax-Span-122">2</span></span></span><span id="MathJax-Span-123"><span id="MathJax-Span-124">(</span><span id="MathJax-Span-125">g</span><span id="MathJax-Span-126">)</span></span><span id="MathJax-Span-127">→</span><span id="MathJax-Span-128"><span id="MathJax-Span-129"><span id="MathJax-Span-130">C</span><span id="MathJax-Span-131">a</span><span id="MathJax-Span-132">C</span><span id="MathJax-Span-133"><span id="MathJax-Span-134">O</span><span id="MathJax-Span-135"><span id="MathJax-Span-136">3</span></span></span><span id="MathJax-Span-137"><span id="MathJax-Span-138">(</span><span id="MathJax-Span-139">s</span><span id="MathJax-Span-140">)</span></span><span id="MathJax-Span-141">+</span><span id="MathJax-Span-142"><span id="MathJax-Span-143">H</span><span id="MathJax-Span-144"><span id="MathJax-Span-145">2</span></span></span><span id="MathJax-Span-146">O</span><span id="MathJax-Span-147"><span id="MathJax-Span-148">(</span><span id="MathJax-Span-149">l</span><span id="MathJax-Span-150">)</span></span></span><span id="MathJax-Span-151"><span id="MathJax-Span-152"><span id="MathJax-Span-153">cloudiness</span></span></span></span></span></span></span></span></span></div> </div> </div>
- Question 12 of 41
12. Question
2 pointsThe correct order of acidic strength of CrO3 , CrO2 , Cr2O3 and CrO
- CrO2 > CrO3 > Cr2O3 > CrO
- CrO3 < CrO2 < Cr2O3 < CrO
- CrO3 > CrO2 > Cr2O3 > CrO
- CrO2 > Cr2O3 > CrO > CrO3
CorrectMore the oxidation state Cro(+2) < cr2o3(+3)<cro3 (+6),
more acidic strength. CrO3 > Cr2O3> CrO
in CrO2 O.S. of Cr = +4
IncorrectMore the oxidation state Cro(+2) < cr2o3(+3)<cro3 (+6),
more acidic strength. CrO3 > Cr2O3> CrO
in CrO2 O.S. of Cr = +4
- Question 13 of 41
13. Question
2 pointsMn²+ forms a complex with Br‾ ion.The magnetic moment of complex is 5.92 BM the probable geometry & formula of the complex
A.Tetrahedral, [MnBr4]2−
B. Square planer, [MnBr4]2−
C. Octahedral, [MnBr6]4−
D.Trigonal planar, [MnBr5]CorrectThe oxidation state of Mn in [MnBr4]2-− is +2 and since its magnetic moment is 5.92 BM
This implies( = 5.92 BM, n=5. Hence Mn has 5 unpaired electrons.As Br is a weak field ligand, therefore, this also implies that the pairing of electrons will not take place and electronic configuration of Mn will be 3d54s0.Now, 4s and 4p orbital of Mn participate in hybridization and the hybridization is sp³ and the geometry will be tetrahedral.IncorrectThe oxidation state of Mn in [MnBr4]2-− is +2 and since its magnetic moment is 5.92 BM
This implies( = 5.92 BM, n=5. Hence Mn has 5 unpaired electrons.As Br is a weak field ligand, therefore, this also implies that the pairing of electrons will not take place and electronic configuration of Mn will be 3d54s0.Now, 4s and 4p orbital of Mn participate in hybridization and the hybridization is sp³ and the geometry will be tetrahedral. - Question 14 of 41
14. Question
2 pointsWhich is incorrectly given according to order indicated
- F2 > Cl2 > Br2 > I2 ; oxidising power
- HI > HBr > HCl > HF ; Acidic strength
- F2 > Cl2 > Br2 > I2 ; Bond dissociation enthalpy
- HF > HI > HBr > HCl ; Boiling point
CorrectBond Dissociation Energy order
:- Cl2>Br2>F2>I2
Florine molecule is small and has 3 lonepairs. So, there is great repulsion among them. Other halogens have vacant d orbitals to keep their lone pair so there is not much repulson. So, flourine molecule breaks easily.
The boiling points of HF,HCl,HBr and HI follow the order HF>HI>HBr>HCl.
HF is hydrogen bonded, thus has highest boiling point, and it is liquid at or below 19oC. The remaining hydrogen halides are gaseous and their boiling points depend on the van der waal’s forces. Larger the size (or molecular mass), greater are the van der Waal’s forces, hence higher is the boiling point.
IncorrectBond Dissociation Energy order
:- Cl2>Br2>F2>I2
Florine molecule is small and has 3 lonepairs. So, there is great repulsion among them. Other halogens have vacant d orbitals to keep their lone pair so there is not much repulson. So, flourine molecule breaks easily.
The boiling points of HF,HCl,HBr and HI follow the order HF>HI>HBr>HCl.
HF is hydrogen bonded, thus has highest boiling point, and it is liquid at or below 19oC. The remaining hydrogen halides are gaseous and their boiling points depend on the van der waal’s forces. Larger the size (or molecular mass), greater are the van der Waal’s forces, hence higher is the boiling point.
- Question 15 of 41
15. Question
2 pointsThe CFSE ( crystal field stabilization energy) in units of D0for [CoF3(H2O)3]
CorrectCo3+ has a high te dency to form low spin compound by having stable d6 configuration ie high cfse
now here though H2O is moderately strong ligand still it forms d6IncorrectCo3+ has a high te dency to form low spin compound by having stable d6 configuration ie high cfse
now here though H2O is moderately strong ligand still it forms d6 - Question 16 of 41
16. Question
2 pointsThe crystal field stabilization energy will be highest for
(1)CoF63-
(2)Co(CNS)42-
(3)Mn(H2O)62+
(4)Co(NH3)63+
CorrectIncorrect - Question 17 of 41
17. Question
2 pointsThe correct order of d-orbital splitting in trigonal prismatic geometry is
- dz2>dx2–y2, dxy>dxz, dyz
- dxz, dyz > dx2 – y2 , dxy > dz2
- dxz, dyz > dz2 > dx2 – y2 , dxy
- dz2 > dxy, dzy > dx2 – y2.dxy
Correct
Incorrect - Question 18 of 41
18. Question
2 pointsThe enthalpies of hydration of Ca2+ , Mn+2 & Zn2+ follow the order
- Zn2+ > Mn+2 > Ca+2
- Mn+2 > Zn+2 > Ca+2
- Zn+2 > Ca+2 > Mn+2
- Mn+2 > Ca+2 > Zn+2
CorrectHydration Enthalpy is equals to sum of expected Hydration Enthalpy and CFSE value for complex compounds. For these ions CFSE is zero so exact hydration enthalpy is equal to expected value. This expected value is large for small size and highly charged ion so the given order is followed.
Zn2+ > Mn2+ > Ca2+
IncorrectHydration Enthalpy is equals to sum of expected Hydration Enthalpy and CFSE value for complex compounds. For these ions CFSE is zero so exact hydration enthalpy is equal to expected value. This expected value is large for small size and highly charged ion so the given order is followed.
Zn2+ > Mn2+ > Ca2+
- Zn2+ > Mn+2 > Ca+2
- Question 19 of 41
19. Question
2 pointsThe spinels MgFe2O4 and MgAl2O4 respectively are
CorrectA common example of a normal spinel is MgAl2O4. Inverse spinel: For an ideal “inverse” spinel structure (such as for MgFe2O4), all of the Mg resides on octahedral sites, and the Fe is distributed equally over the remaining octahedral sites and all of the tetrahedral sites
Etra info : MgAl2O4 is diamagnetic since all the electrons in the metal ions are paired up.
MgAl2O4 is a normal spinel since both the divalent and trivalent ions are non transition metal ions.
IncorrectA common example of a normal spinel is MgAl2O4. Inverse spinel: For an ideal “inverse” spinel structure (such as for MgFe2O4), all of the Mg resides on octahedral sites, and the Fe is distributed equally over the remaining octahedral sites and all of the tetrahedral sites
Etra info : MgAl2O4 is diamagnetic since all the electrons in the metal ions are paired up.
MgAl2O4 is a normal spinel since both the divalent and trivalent ions are non transition metal ions.
Hint
Structures of Inverse spinels (B(AB)O4): The AII ions occupy the octahedral voids, whereas one half of BIII ions occupy the tetrahedral voids and the other half occupy octahedral sites. It can be represented as: (BIII)tet(AIIBIII)octO4.
- Question 20 of 41
20. Question
2 pointsWhich of the following complex ions absorbs the light of minimum wavelength?
A .[Co(H2O)6]3+
B .[CoF6]3−
C .[Co(CN)6]3−
D .[Co(NH3)6]3+
Correct<div style="margin: 0px;padding: 0px;border: 0px;font-size: 18px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;color: #000000;font-family: Karla;letter-spacing: -0.36px"> <div style="margin: 0px;padding: 0px;border: 0px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;letter-spacing: -0.36px">Wavelength of light absorbed <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mrel" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">∝1/</span></span></span></span><span aria-hidden="true">stbility of complex</span></div> <div style="margin: 0px;padding: 0px;border: 0px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;letter-spacing: -0.36px">In all given complexes Co is present in <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">+</span><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">3</span></span></span></span> state and among the given ligands <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="mopen" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">(</span><span class="mord mathdefault" style="margin: 0px 0.07153em 0px 0px;padding: 0px;border: 0px;background: transparent;position: static;font-family: KaTeX_Math;font-style: italic">C</span><span class="mord mathdefault" style="margin: 0px 0.10903em 0px 0px;padding: 0px;border: 0px;background: transparent;position: static;font-family: KaTeX_Math;font-style: italic">N</span><span class="mclose" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">)</span></span><span class="msupsub" style="margin: 0px;padding: 2px 0px;border: 0px;background: transparent;position: relative"><span class="vlist-t" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static;border-collapse: collapse"><span class="vlist-r" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="vlist" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;vertical-align: bottom;height: 0.911231em"><span style="margin: 0px 0.05em 0px 0px;padding: 0px;border: 0px;background: transparent;position: relative;height: 0px;top: -3.2029em"><span class="sizing reset-size6 size3 mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 0.7em;background: transparent;position: static"><span class="mord mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 12.6px;background: transparent;position: static"><span class="mord mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 12.6px;background: transparent;position: static">−</span></span></span></span></span></span></span></span></span></span></span></span> is the strongest ligand. Hence <span aria-hidden="true">[Co(CN)6]3−</span> is most stable, thus it absorbs light of minimum wavelength. Thus answer is option C</div> </div>
Incorrect<div style="margin: 0px;padding: 0px;border: 0px;font-size: 18px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;color: #000000;font-family: Karla;letter-spacing: -0.36px"> <div style="margin: 0px;padding: 0px;border: 0px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;letter-spacing: -0.36px">Wavelength of light absorbed <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mrel" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">∝1/</span></span></span></span><span aria-hidden="true">stbility of complex</span></div> <div style="margin: 0px;padding: 0px;border: 0px;background-image: initial;background-position: initial;background-size: initial;background-repeat: initial;background-attachment: initial;letter-spacing: -0.36px">In all given complexes Co is present in <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">+</span><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">3</span></span></span></span> state and among the given ligands <span class="katex" style="margin: 0px;padding: 0px;border: 0px;font-size: 1em;background: transparent;font-weight: inherit;font-family: KaTeX_Main, 'Times New Roman', serif;line-height: inherit;position: relative"><span class="katex-html" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static" aria-hidden="true"><span class="base" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;width: min-content"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="mord" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="mopen" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">(</span><span class="mord mathdefault" style="margin: 0px 0.07153em 0px 0px;padding: 0px;border: 0px;background: transparent;position: static;font-family: KaTeX_Math;font-style: italic">C</span><span class="mord mathdefault" style="margin: 0px 0.10903em 0px 0px;padding: 0px;border: 0px;background: transparent;position: static;font-family: KaTeX_Math;font-style: italic">N</span><span class="mclose" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static">)</span></span><span class="msupsub" style="margin: 0px;padding: 2px 0px;border: 0px;background: transparent;position: relative"><span class="vlist-t" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static;border-collapse: collapse"><span class="vlist-r" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: static"><span class="vlist" style="margin: 0px;padding: 0px;border: 0px;background: transparent;position: relative;vertical-align: bottom;height: 0.911231em"><span style="margin: 0px 0.05em 0px 0px;padding: 0px;border: 0px;background: transparent;position: relative;height: 0px;top: -3.2029em"><span class="sizing reset-size6 size3 mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 0.7em;background: transparent;position: static"><span class="mord mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 12.6px;background: transparent;position: static"><span class="mord mtight" style="margin: 0px;padding: 0px;border: 0px;font-size: 12.6px;background: transparent;position: static">−</span></span></span></span></span></span></span></span></span></span></span></span> is the strongest ligand. Hence <span aria-hidden="true">[Co(CN)6]3−</span> is most stable, thus it absorbs light of minimum wavelength. Thus answer is option C</div> </div>
- Question 21 of 41
21. Question
2 pointsWhich of the following does not increase when we move from left to right along a period in the periodic table?
CorrectIncorrect - Question 22 of 41
22. Question
2 pointsWhich of the following processes is endothermic?
CorrectH(g) → H+ (g) + e–
IncorrectH(g) → H+ (g) + e–
- Question 23 of 41
23. Question
2 pointsWhich of the following processes is endothermic?
CorrectIncorrect - Question 24 of 41
24. Question
2 pointsWhich statement is correct about a 1H NMR spectrum of 99% deuterium-enriched CDCl3?
CorrectA signal is observed due to 1H
IncorrectA signal is observed due to 1H
- Question 25 of 41
25. Question
2 pointsWhich molecule is non-polar?
CorrectBH3
IncorrectBH3
- Question 26 of 41
26. Question
2 pointsWhich statement is incorrect?
CorrectThe boiling point of the hydride of the first member of each of groups 14-17 is anomalous within the group
IncorrectThe boiling point of the hydride of the first member of each of groups 14-17 is anomalous within the group
- Question 27 of 41
27. Question
2 pointsWhich of the following is a saline hydride?
CorrectNaH
IncorrectNaH
- Question 28 of 41
28. Question
2 pointsWhich of the following has a polymeric structure in the solid state?
CorrectBeH2
IncorrectBeH2
- Question 29 of 41
29. Question
2 pointsHow many H environments are present in the static structure of [ReH9]2–?
Correct2
Incorrect2
- Question 30 of 41
30. Question
2 pointsWhat is the coordination number of Al in the solid state structure of AlH3?
Correct6
Incorrect6
- Question 31 of 41
31. Question
2 pointsThe reaction of Ph2PH with BuLi would,
Correctproduce LiPPh2
Incorrectproduce LiPPh2
- Question 32 of 41
32. Question
2 pointsWhich statement is incorrect about the reaction of N2 and H2 to give NH3?
CorrectΔS for the forward reaction is positive
IncorrectΔS for the forward reaction is positive
- Question 33 of 41
33. Question
2 pointsAll the following hydrogen-bonded interactions have been observed in the solid state. Which of the following is likely to be the weakest?
CorrectC–H—O
IncorrectC–H—O
- Question 34 of 41
34. Question
2 pointsWhich statement is incorrect?
CorrectGaBH6 contains [BH6]3– ions
IncorrectGaBH6 contains [BH6]3– ions
- Question 35 of 41
35. Question
2 pointsHydrogen bonding plays an important role in all except one of the following. Which is the odd one out?
CorrectThe reversible absorption of H2 by palladium metal
IncorrectThe reversible absorption of H2 by palladium metal
- Question 36 of 41
36. Question
2 pointsIn which reaction is H2 liberated?
CorrectNaH + H2O →
IncorrectNaH + H2O →
- Question 37 of 41
37. Question
2 pointsIsotopes of hydrogen differ in,
Correctthe number of neutrons they possess
Incorrect - Question 38 of 41
38. Question
2 pointsWhich pair of solvents, X and Y, is expected to show classical intermolecular hydrogen bonding between X and Y?
CorrectX = EtOH, Y = EtNH2
IncorrectX = EtOH, Y = EtNH2
- Question 39 of 41
39. Question
2 pointsWhich of the following reactions does not produce H2?
CorrectIncorrect - Question 40 of 41
40. Question
2 pointsWhich of the following molecules possesses a dipole moment?
CorrectPH3
IncorrectPH3
- Question 41 of 41
41. Question
2 pointsWhich metal does not liberate H2 from dilute aqueous hydrochloric acid at 298 K?
CorrectIncorrectCu
Leaderboard: Inorganic – Chemistry (CSIR NET)
| Pos. | Name | Entered on | Points | Result |
|---|---|---|---|---|
| Table is loading | ||||
| No data available | ||||
CSIR-NET Cut off for chemical Science Paper
| JRF | JRF | JRF | JRF | JRF | LS | LS | LS | LS | LS | |
| Exam | Unreserved | OBC | SC | ST | PwD | Unreserved | OBC | SC | ST | PwD |
| Dec 2017 | 58.75% | 51.50% | 42.25% | 30.75% | 25.00 % | 52.88% | 46.35% | 38.03% | 27.68% | 25.00% |
| Jun 2017 | 55.50% | 48.25% | 40.25% | 30.00% | 28.75% | 49.55% | 43.43% | 36.22% | 27.00% | 25.87% |
| Dec 2016 | 51.50% | 44.25% | 36.75% | 27.00% | 25.25% | 46.35% | 39.83% | 33.08% | 25.00% | 25.00% |
| Jun 2016 | 50.25% | 43.25% | 34.50% | 25.00% | 27.75% | 45.23% | 38.93% | 31.05% | 25.00% | 25.00% |
| Dec 2015 | 56.75% | 50.50% | 40.75% | 32.75% | 33.50% | 51.08% | 45.45% | 36.68% | 29.48% | 30.15% |
