MCQs Test Based on Previous Year Question Paper | B.Sc. Chemistry VI Semester
Short Description: Practice important MCQs based on previous year question papers for B.Sc. Chemistry 6th Semester. Improve your exam preparation with these solved multiple-choice questions.
Introduction
Are you preparing for the B.Sc. Chemistry VI Semester exam? You’re in the right place! In this post, we present a collection of solved MCQs based on previous year B.Sc. VI semester question papers. These questions help you understand the exam pattern and boost your confidence with accurate practice.
Whether you’re targeting university exams or competitive tests, solving past-year-based MCQs is one of the best strategies to score well.
Key Features of This MCQ Test
- Based on B.Sc. Chemistry VI Semester syllabus
- Derived from previous year question papers
- Ideal for revision and self-assessment
- Useful for university exams and entrance tests like CUET
Spectroscopy MCQ Test Based on Previous Year Question Paper
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Information
This MCQ test is tailored for B.Sc. Chemistry 6th semester students across Indian state universities. Aligned with common syllabus patterns, it covers key topics like spectroscopy, coordination chemistry, and organic reaction mechanisms. Ideal for practice, self-assessment, and final exam revision, the test helps boost understanding, accuracy, and confidence.
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Question 1 of 30
1. Question
Category: SpectroscopyAn auxochrome is one which is
(A) Colour enhancing
(B) Extending conjugation
(C) Atom with 1 lone pair of electron
(D) All of theseCorrect
Incorrect
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Question 2 of 30
2. Question
Category: SpectroscopyHypsochromic effect is also called:
(A) Blue shift
(B) Red shift
(C) Yellow shift
(D) Purple effectCorrect
Incorrect
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Question 3 of 30
3. Question
Category: SpectroscopyThe equation
Io log₁₀ I = ECl is an expression of:
(A) Beer’s law
(B) Lambert’s law
(C) Both (A) and (B)
(D) None of theseCorrect
Solution
The equation represents both Beer’s Law and Lambert’s Law.Incorrect
Sorry, you are incorrect, The equation represents both Beer’s Law and Lambert’s Law.
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Question 4 of 30
4. Question
Category: SpectroscopyHigher value of energy is required for the transition of electron:
(A) π → π*
(B) n → π*
(C) n → σ*
(D) σ → σ*Correct
The order of energy required for various transitions is: σ → σ* > n → σ* > π → π* > n → π*. This is because sigma bonds are generally stronger and require more energy to break compared to pi bonds.
Incorrect
Oops! you are incorrect, The order of energy required for various transitions is: σ → σ* > n → σ* > π → π* > n → π*. This is because sigma bonds are generally stronger and require more energy to break compared to pi bonds.
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Question 5 of 30
5. Question
Category: SpectroscopyKa band originated as a result of:
(A) π → π*
(B) n → π*
(C) σ → σ*
(D) n → π* and σ → σ*Correct
The term “K-band” is associated with conjugated systems, and its appearance indicates the presence of extended π networks within a molecule. K-bands in UV-visible spectroscopy specifically refer to absorption bands arising from π → π* transitions in conjugated systems.
Incorrect
K-bands in UV-visible spectroscopy specifically refer to absorption bands arising from π → π* transitions in conjugated systems.
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Question 6 of 30
6. Question
Category: SpectroscopyThe base value of homoannular diene is:
(A) 215
(B) 212
(C) 253
(D) 217Correct
Homoannular diene, also known as a cisoid diene, in UV-Vis spectroscopy is 253 nm.
Incorrect
moannular diene, also known as a cisoid diene, in UV-Vis spectroscopy is 253 nm.
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Question 7 of 30
7. Question
Category: SpectroscopyThe value of extinction coefficient increases with:
Correct
The extinction coefficient increases with both conjugation and chromophore length. Longer conjugated systems and larger chromophores generally lead to higher absorption intensity and thus, a larger extinction coefficient.
Incorrect
The extinction coefficient increases with both conjugation and chromophore length. Longer conjugated systems and larger chromophores generally lead to higher absorption intensity and thus, a larger extinction coefficient.
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Question 8 of 30
8. Question
Category: SpectroscopyCalculate λmax for the compound
Correct
Your calculation is spot on! You’re applying Woodward-Fieser rules to estimate the λmax (lambda max) for a conjugated diene system. Here’s a breakdown for clarity:
- Base value for a homoannular diene = 253 nm
- Alkyl substituents (4 total) = 4 × 5 = 20 nm
- Exocyclic double bonds (2 total) = 2 × 5 = 10 nm
- Additional conjugated double bond = 30 nm
Estimated λmax = 253 + 20 + 10 + 30 = 313 nm
Incorrect
Woodward-Fieser rules estimate the λmax (lambda max) for a conjugated diene system. Here’s a breakdown for clarity:
- Base value for a homoannular diene = 253 nm
- Alkyl substituents (4 total) = 4 × 5 = 20 nm
- Exocyclic double bonds (2 total) = 2 × 5 = 10 nm
- Additional conjugated double bond = 30 nm
Estimated λmax = 253 + 20 + 10 + 30 = 313 nm
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Question 9 of 30
9. Question
Category: SpectroscopyWhich of the following cannot be detected with the help of UV-spectroscopy?
Correct
Incorrect
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Question 10 of 30
10. Question
Category: SpectroscopyOvertones are mainly observed in:
Correct
Incorrect
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Question 11 of 30
11. Question
Category: SpectroscopyFormula for total number of vibration modes for non-linear molecule:
Correct
Incorrect
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Question 12 of 30
12. Question
Category: SpectroscopyWhich region of the IR spectrum is typically used for detection of functional groups?
(A) 1300 – 667 cm⁻¹
(B) 4000 – 1300 cm⁻¹
(C) 4000 – 667 cm⁻¹
(D) 3600 – 3200 cm⁻¹Correct
Incorrect
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Question 13 of 30
13. Question
Category: SpectroscopyThe total number of modes of vibration for H₂O molecule are:
(A) 3
(B) 4
(C) 5
(D) 6Correct
Incorrect
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Question 14 of 30
14. Question
Category: SpectroscopyWhich region of the IR spectra is used to identify the presence of an -OH group?
(A) 3200 – 3000 cm⁻¹
(B) 3600 – 3200 cm⁻¹
(C) 3000 – 2500 cm⁻¹
(D) 2300 – 2100 cm⁻¹Correct
Incorrect
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Question 15 of 30
15. Question
Category: SpectroscopyC–H stretch of aldehyde group shows IR absorption frequency in the range of:
(A) 3000 cm⁻¹
(B) 3200 cm⁻¹
(C) 2850 – 2900 cm⁻¹
(D) 2650 – 2880 cm⁻¹Correct
Incorrect
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Question 16 of 30
16. Question
Category: SpectroscopyMolecule which is IR active:
(A) F₂
(B) H₂
(C) N₂
(D) CO₂Correct
Incorrect
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Question 17 of 30
17. Question
Category: SpectroscopyHooke’s law for the vibrational frequency may be represented as:
(A) F = KQ
(B) F = –KQ
(C) F = ½ KQ²
(D) F = KQ²F = the restoring force exerted by the spring.
K = the spring constant, which is a measure of the spring’s stiffness (how much force is needed to stretch or compress it by a certain amount).Correct
Incorrect
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Question 18 of 30
18. Question
Category: SpectroscopyFor a pure rotational spectrum, the selection rule is:
(A) ΔJ = +1
(B) ΔJ = +2
(C) ΔJ = ±1
(D) ΔJ = 0Correct
Incorrect
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Question 19 of 30
19. Question
Category: SpectroscopyWhich of the following is NOT a type of bending mode?
(A) Scissoring
(B) Rocking
(C) Stretching
(D) WaggingCorrect
Incorrect
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Question 20 of 30
20. Question
Category: SpectroscopyRead the following data.
IR Spectra Observation:
The IR spectrum of an oxygen-containing compound shows three significant absorption peaks at the following wave numbers:2960 cm⁻¹ — Corresponds to C–H stretching (alkyl group)
1720 cm⁻¹ — Indicative of a C=O (carbonyl) stretching, commonly seen in aldehydes, ketones, esters, or carboxylic acids
750 cm⁻¹ — Suggests C–H bending (out-of-plane bending of aromatic or alkyl substituted chains)
The wavelength corresponding to the peak at 1720 cm-1 is
(A) 5.81 μm
(B) 6.17 μm
(C) 5.81 nm
(D) 6.17 nmCorrect
Incorrect
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Question 21 of 30
21. Question
Far IR region mainly consists of:
(A) 0.8 μ to 2.5 μ
(B) 2.5 μ to 15 μ
(C) 15 μ to 200 μ
(D) None of theseCorrect
(C) 15 μm to 200 μm ✅
This range is part of the infrared spectrum and is typically used in applications like thermal imaging, molecular vibration studies, and astronomy.
Incorrect
(C) 15 μm to 200 μm ✅
This range is part of the infrared spectrum and is typically used in applications like thermal imaging, molecular vibration studies, and astronomy.
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Question 22 of 30
22. Question
The correct order of the decreasing frequency of electromagnetic radiation is:
(A) X-ray > UV > IR > Visible
(B) UV > IR > X-ray > Visible
(C) X-ray > UV > Visible > IR
(D) Visible > UV > IR > X-rayCorrect
Correct answer: (C) X-ray > UV > Visible > IR ✅
Explanation: Frequency decreases from X-rays to IR.
Incorrect
Correct answer: (C) X-ray > UV > Visible > IR ✅
Explanation: Frequency decreases from X-rays to IR.
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Question 23 of 30
23. Question
Which type of group can be identified in IR spectroscopy?
(A) Amide
(B) Carbonyl
(C) Nitro
(D) All of theseCorrect
Correct answer: (D) All of these ✅
Short explanation: IR spectroscopy can identify amide, carbonyl, and nitro groups based on their characteristic absorption bands.
Amides typically show a strong carbonyl stretch around 1640–1690 cm⁻¹ and an N-H stretch around 3200–3400 cm⁻¹.
Carbonyl groups (like in aldehydes, ketones, carboxylic acids, etc.) generally absorb around 1725 cm⁻¹.
Nitro groups often have strong asymmetric and symmetric stretching bands around 1500–1600 cm⁻¹ and 1300–1350 cm⁻¹.
Incorrect
Correct answer: (D) All of these ✅
Short explanation: IR spectroscopy can identify amide, carbonyl, and nitro groups based on their characteristic absorption bands.
Amides typically show a strong carbonyl stretch around 1640–1690 cm⁻¹ and an N-H stretch around 3200–3400 cm⁻¹.
Carbonyl groups (like in aldehydes, ketones, carboxylic acids, etc.) generally absorb around 1725 cm⁻¹.
Nitro groups often have strong asymmetric and symmetric stretching bands around 1500–1600 cm⁻¹ and 1300–1350 cm⁻¹.
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Question 24 of 30
24. Question
The angular wave function of hydrogen depends upon the quantum numbers:
(A) n and l only
(B) l and only ml
(C) ml only
(D) l, ml and nCorrect
Correct answer: (B) l and only ml ✅
Short explanation:
The angular wave function (also called the spherical harmonics part) of the hydrogen atom depends only on the azimuthal quantum number (l) and the magnetic quantum number (ml) — not on the principal quantum number (n), which affects only the radial part.Incorrect
Correct answer: (B) l and only ml ✅
Short explanation:
The angular wave function (also called the spherical harmonics part) of the hydrogen atom depends only on the azimuthal quantum number (l) and the magnetic quantum number (ml) — not on the principal quantum number (n), which affects only the radial part. -
Question 25 of 30
25. Question
Acceptable wave function for a quantum particle must be:
(A) Odd
(B) Even
(C) Single valued and continuous
(D) Physically significantCorrect
Correct answer: (C) Single valued and continuous ✅
Short explanation:
An acceptable wave function must be single-valued (i.e., the wave function must have only one value for each point in space) and continuous (i.e., it should not have any sudden jumps or discontinuities). This ensures the wave function is physically meaningful.Incorrect
Correct answer: (C) Single valued and continuous ✅
Short explanation:
An acceptable wave function must be single-valued (i.e., the wave function must have only one value for each point in space) and continuous (i.e., it should not have any sudden jumps or discontinuities). This ensures the wave function is physically meaningful. -
Question 26 of 30
26. Question
The motion of wave particle is similar to:
(A) Photon
(B) Waves
(C) Classical particle
(D) Quantum particleCorrect
Correct answer: (B) Waves ✅
Short explanation:
The motion of a wave-particle (like an electron) is similar to waves because it exhibits both particle-like and wave-like properties, a concept known as wave-particle duality.Incorrect
Correct answer: (B) Waves ✅
Short explanation:
The motion of a wave-particle (like an electron) is similar to waves because it exhibits both particle-like and wave-like properties, a concept known as wave-particle duality. -
Question 27 of 30
27. Question
The concept of matter wave was suggested by:
(A) Heisenberg
(B) de Broglie
(C) Schrödinger
(D) LaplaceCorrect
Correct answer: (B) de Broglie ✅
Short explanation:
The concept of matter waves was suggested by Louis de Broglie in 1924, proposing that particles, like electrons, have wave-like properties.Incorrect
Correct answer: (B) de Broglie ✅
Short explanation:
The concept of matter waves was suggested by Louis de Broglie in 1924, proposing that particles, like electrons, have wave-like properties. -
Question 28 of 30
28. Question
What is the main point of de-Broglie equation?
(A) The position of light cannot be precisely determined
(B) Matter only behaves like a particle
(C) Matter has wave-like properties
(D) Einstein’s theory of relativity was incorrectCorrect
Correct answer: (C) Matter has wave-like properties ✅
Short explanation:
The main point of de Broglie’s equation is that matter (such as electrons) exhibits wave-like properties, a concept central to wave-particle duality.Incorrect
Correct answer: (C) Matter has wave-like properties ✅
Short explanation:
The main point of de Broglie’s equation is that matter (such as electrons) exhibits wave-like properties, a concept central to wave-particle duality. -
Question 29 of 30
29. Question
Which two characteristics are variables in Heisenberg’s uncertainty principle?
(A) Position and momentum
(B) Wavelength and distance
(C) Charge and displacement
(D) Atomic radius and frequencyCorrect
Correct answer: (A) Position and momentum ✅
Short explanation:
Heisenberg’s uncertainty principle states that the position and momentum of a quantum particle cannot both be precisely determined at the same time. The more accurately one is measured, the less accurately the other can be known.Incorrect
Correct answer: (A) Position and momentum ✅
Short explanation:
Heisenberg’s uncertainty principle states that the position and momentum of a quantum particle cannot both be precisely determined at the same time. The more accurately one is measured, the less accurately the other can be known. -
Question 30 of 30
30. Question
Energy of a wave divided by its momentum gives:
Correct
Correct answer: (C) Phase velocity ✅
Short explanation:
The energy of a wave divided by its momentum gives the phase velocity, which describes the speed at which the wave’s phase propagates through space.Incorrect
Correct answer: (C) Phase velocity ✅
Short explanation:
The energy of a wave divided by its momentum gives the phase velocity, which describes the speed at which the wave’s phase propagates through space.
Leaderboard:
Leaderboard: Spectroscopy MCQ Test Based on Previous Year Question Paper
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Why Practice Previous Year-Based MCQs?
- Familiarity with Question Types: Understanding how questions are framed helps in tackling similar ones.
- Time Management: Practicing MCQs improves your speed and accuracy.
- Quick Revision: MCQs cover core concepts quickly and effectively.
- Exam Readiness: You’ll get a real-time feel of the actual exam.
Tips to Maximize Your Score
- Practice daily for at least 30 minutes.
- Focus more on repeated or frequently asked questions.
- Attempt MCQs in a time-bound manner.
- Review your wrong answers to avoid repeating mistakes.
FAQs
Q1: Are these MCQs based on the official syllabus of B.Sc. Chemistry VI Semester?
Ans: Yes, these MCQs are designed according to the university syllabus and based on previous year question papers.
Q2: Can I download these MCQs in PDF format?
Ans: Yes, we will soon provide a downloadable PDF version for offline practice.
Q3: Are answer keys provided?
Ans: Yes, each MCQ is provided with the correct answer for self-evaluation.
Q4: How often is this page updated with new MCQs?
Ans: We update it every semester with new sets from the latest exams.
Conclusion
Practicing MCQs based on previous year question papers for B.Sc. Chemistry VI Semester is a smart and effective way to prepare. Bookmark this page and keep practicing regularly to excel in your exams.
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